7th Grade School Project
 
    Well first of all, 7^-5 pretty much means seven to the negitive fifth power. The answer to this problem is going to be negitive because a negitive multiplied by a positive is always negitive. You need to use the (^) symbol to show that is an exponent because you can't type that on a keyboard. A more advanced problem would be something like this: (2x^3y)^5. To solve, You first muntiply 2^5 which is 32. Then, you would first multiply the first set of exponets (3*5=15). That is the first answer to this problem. If a variable has no exponent, it is automatically one. So then 1*5=5 so the final answer would be 32x^15y^5. 

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